# Re: [R] dynamic lists (data frames?)

Date: Wed 28 Sep 2005 - 01:57:26 EST

Thanks for your replies but I think my example was a little to simple the actual code I'm using is:

f_haardisolve<-function(v_dataset){

l_cooef<-list() #holder for cooefficents     i_count<-1 #identity counter

while(length(v_dataset)>0){

```        #seperate odd and even points
v_dataset<-f_splitpoints(v_dataset)

v_dataset<-f_haarpredict(v_dataset)
v_dataset<-f_haaruplift(v_dataset)

str_idx<-paste('c',i_count,sep='')
l_cooef
```

\$str_idx<-v_dataset[c((length(v_dataset)/2)+1:(length(v_dataset)/2))] #should be no wrap on the previous line

v_dataset<-v_dataset[c(1:length(v_dataset)/2)]

i_count<-i_count+1
}
l_cooef
}

In this particular case I could probably calculate the number of iterations and use l_cooef<-names() but more is there a more generic method for adding another column of data?

On Tue, 2005-27-09 at 10:39 -0400, tom wright wrote:
> Can someone please show me what I need to get something like this to
> work
>
> for(a in c(1:5)){
> data\$a<-c(a:10)
> }
>
> so that i end up with a structure
> data\$1<-[1,2,3,4,5,6,7,8,9,10]
> data\$2<-[2,3,4,5,67,8,9,10]
> data\$3<-[3,4,5,67,8,9,10]
> data\$4<-[4,5,67,8,9,10]
> data\$5<-[5,67,8,9,10]
>
> Tom
>
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