From: Mikkel Grum <mi2kelgrum_at_yahoo.com>

Date: Mon 02 Jan 2006 - 18:27:00 EST

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Mon Jan 02 18:33:04 2006

Date: Mon 02 Jan 2006 - 18:27:00 EST

I want to do something like df[df$b %in% df2[i, 2], ]
where df$b is a numeric vector and df2[i, 2] is a
factor with

levels like "7:9, 12:14". For example:

a <- c(paste("A", 1:10, sep = ""), paste("B", 1:10,
sep = ""))

b <- 1:20

df <- as.data.frame(cbind(a, b))

df$b <- as.numeric(levels(df$b))[as.integer(df$b)]

f <- c("X", "Y", "Z")

g <- c("1:6", "7:9, 12:14", "18")

df2 <- as.data.frame(cbind(f, g))

i <- 2

df[df$b %in% df2[i, 2], ] # or

df[df$b %in% levels(df2)[as.integer(df2[i, 2])], ] #
this is the closest I've got

The results I want is given by

> df[df$b %in% c(7:9, 12:14), ]

a b

7 A7 7

8 A8 8

9 A9 9

12 B2 12

13 B3 13

14 B4 14

Can it be done?

Mikkel Grum

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Mon Jan 02 18:33:04 2006

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