From: Marc Schwartz <MSchwartz_at_mn.rr.com>

Date: Wed 04 Jan 2006 - 12:04:14 EST

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Wed Jan 04 13:09:36 2006

Date: Wed 04 Jan 2006 - 12:04:14 EST

On Tue, 2006-01-03 at 18:57 -0600, Eberhard F Morgenroth wrote:

> I have a list as follows

*>
**> P <- list(A = c("CS", "CX"),
**> B = 1:4,
**> Y = c(4, 9))
**>
**> I now would like to prepare a new list where the rows of the new list
**> provide all possible combinations of the elements in the orginal list.
**> Thus, the result should be the following
**>
**> CS 1 4
**> CS 1 9
**> CS 2 4
**> CS 2 9
**> CS 3 4
**> CS 3 9
**> CS 4 4
**> CS 4 9
**> CX 1 4
**> CX 1 9
**> CX 2 4
**> CX 2 9
**> CX 3 4
**> CX 3 9
**> CX 4 4
**> CX 4 9
**>
**> Is there a simple routine in R to create this list of all possible
**> combinations? The routine will be part of a function with the list "P"
**> as an input. "P" will not always have the same number of elements and
**> each element in the list "P" may have different numbers of values.
*

See ?expand.grid

> expand.grid(P)

A B Y

1 CS 1 4

2 CX 1 4

3 CS 2 4

4 CX 2 4

5 CS 3 4

6 CX 3 4

7 CS 4 4

8 CX 4 4

9 CS 1 9

10 CX 1 9

11 CS 2 9

12 CX 2 9

13 CS 3 9

14 CX 3 9

15 CS 4 9

16 CX 4 9

**HTH,
**
Marc Schwartz

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Wed Jan 04 13:09:36 2006

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