Re: [R] yet another vectorization question

From: Adrian Dusa <adi_at_roda.ro>
Date: Tue 31 Jan 2006 - 02:47:53 EST

On Monday 30 January 2006 14:40, Philippe Grosjean wrote:
> Hello,
> Not exactly the same. By the way, why do you use do.call()? Couldn't you
> do simply:
> expand.grid(split(t(replicate(3, c(0, 1, NA))), 1:3))
> Best,
> Philippe Grosjean
>
> Jacques VESLOT wrote:
> > this looks similar:
> > do.call(expand.grid,split(t(replicate(3,c(0,1,NA))),1:3))

Sigh, what a pity. It is indeed not the same... So close to a one-liner though.

I come back to my original question: is it possible to modify the content of a matrix, using apply on a different matrix? In my original function, the slow part is: ## ...
for (k in 1:ncol(idk)) {

   end.row <- start.row + nrow(tt) - 1
   return.matrix[start.row:end.row, idk[ , k]] <- tt    start.row <- end.row + 1
}
## ...

I'd like to use apply on the "idk" matrix (to get rid of the for loop) and write the contents of "tt" in the "result.matrix"...

Best,
Adrian

-- 
Adrian DUSA
Romanian Social Data Archive
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          +40 21 3120210 / int.101

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Received on Tue Jan 31 03:02:55 2006

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