Re: [R] reading in a tricky computer program output

From: Gabor Grothendieck <ggrothendieck_at_gmail.com>
Date: Mon 06 Feb 2006 - 02:29:18 EST

Its not clear to me what format you want to put the data in but this will read it into a list, one list element per lower triangular matrix. Modify to suit.

DF <- read.table("myfile.dat", fill = TRUE) id <- cumsum(is.na(DF[,2]))
result <- by(DF, id, as.matrix)

# if the input is in the second format add this line after the above result2 <- lapply(result, function(x) rbind(NA, x))

On 2/5/06, Taka Matzmoto <sell_mirage_ne@hotmail.com> wrote:
> Hi R user
>
> I need to read in some values from a computer program output.
>
> I can't change the output format because the developer of the program
> doesn't allow to change the format of output.
>
> There are two formats.
>
> First one looks like this
>
> if I have 10 variables,
>
> ------------------------------------------------------------------------------------------------------
> [ 1] [2] [3] [4] [5]
> [ 1] 0.000
> [ 2] 0.001 0.000
> [ 3] -0.002 0.019 0.000
> [ 4] 0.012 -0.004 -0.020 0.000
> [ 5] -0.015 0.003 0.011 0.008 0.000
> [ 6] 0.005 -0.008 -0.005 0.002 0.005
> [ 7] 0.008 -0.007 0.013 0.003 0.007
> [ 8] -0.014 -0.011 -0.010 -0.025 0.002
> [ 9] 0.006 0.003 -0.010 0.002 -0.020
> [10] 0.006 0.010 -0.006 0.005 0.008
> [ 6] 0.000
> [ 7] -0.037 0.000
> [ 8] 0.010 0.027 0.000
> [ 9] 0.032 -0.004 0.008 0.000
> [10] -0.008 -0.011 0.015 -0.020 0.000
>
> ------------------------------------------------------------------------------------------------
> NOTE: I put [number] to show that this output is similar to a lower diagonal
> matrix including diagonal. In an ouput there is no [number]
>
>
> The second format looks like this
> --------------------------------------------------------------------------------------
> [1] [2] [3] [4] [5]
> [ 2] -0.002
> [ 3] 0.003 -0.053
> [ 4] -0.026 0.010 0.045
> [ 5] 0.023 -0.008 -0.025 -0.016
> [ 6] -0.012 0.023 0.013 -0.005 -0.011
> [ 7] -0.031 0.031 -0.054 -0.013 -0.027
> [ 8] 0.040 0.042 0.031 0.075 -0.007
> [ 9] -0.012 -0.009 0.023 -0.005 0.037
> [10] -0.013 -0.027 0.014 -0.013 -0.020
> [ 7] 0.127
> [ 8] -0.035 -0.166
> [ 9] -0.083 0.015 -0.027
> [10] 0.021 0.047 -0.052 0.048
> ---------------------------------------------------------------------------------------------------------
> NOTE: I put [number] to show that this output is similar to a lower diagonal
> matrix without diagonal. In an ouput there is no [number]
>
> The problem of this format is the fixed column length ( 5 columns)
>
> To make matter worse, the number of variables keep changing (10, 20, 30, 40,
> 50, 60,70,80,90, and 100) so I need to take into the number of variables
> when I write a R function to read in these numbers.
>
> If the number of variables is 80, the output is very long.
>
> I only came up with this tedious one.
>
> First I read in the output using scan() and then make it a numeric vector
>
> I created 10 character vectors. Creating a 100 variable character vector is
> the most boring things
>
> I have ever done.
>
> one of the character vectors that matchs with the first 10 variable output
> is
>
> first.10<-c(
> "i.001.001",
> "i.002.001","i.002.002",
> "i.003.001","i.003.002","i.003.003",
> "i.004.001","i.004.002","i.004.003","i.004.004",
> "i.005.001","i.005.002","i.005.003","i.005.004","i.005.005",
> "i.006.001","i.006.002","i.006.003","i.006.004","i.006.005",
> "i.007.001","i.007.002","i.007.003","i.007.004","i.007.005",
> "i.008.001","i.008.002","i.008.003","i.008.004","i.008.005",
> "i.009.001","i.009.002","i.009.003","i.009.004","i.009.005",
> "i.010.001","i.010.002","i.010.003","i.010.004","i.010.005",
> "i.006.006",
> "i.007.006","i.007.007",
> "i.008.006","i.008.007","i.008.008",
> "i.009.006","i.009.007","i.009.008","i.009.009",
> "i.010.006","i.010.007","i.010.008","i.010.009","i.010.010"
> )
>
> one of the character vectors that matchs with the second 10 variable output
> is
>
> second.10<-c(
> "i.002.001",
> "i.003.001","i.003.002",
> "i.004.001","i.004.002","i.004.003",
> "i.005.001","i.005.002","i.005.003","i.005.004",
> "i.006.001","i.006.002","i.006.003","i.006.004","i.006.005",
> "i.007.001","i.007.002","i.007.003","i.007.004","i.007.005",
> "i.008.001","i.008.002","i.008.003","i.008.004","i.008.005",
> "i.009.001","i.009.002","i.009.003","i.009.004","i.009.005",
> "i.010.001","i.010.002","i.010.003","i.010.004","i.010.005",
> "i.007.006",
> "i.008.006","i.008.007",
> "i.009.006","i.009.007","i.009.008",
> "i.010.006","i.010.007","i.010.008","i.010.009"
> )
>
> and then assign the character vector to the numeric vector by
>
> names<-first.10
> first.10 = numeric.vector
> combined.one <- cbind(names,first.10)
> container <- diag(10)
> for (i in 1:(10*10))
> {
> k <- as.numeric(substr(combined.one[i,1],7,9))
> l <- as.numeric(substr(combined.one [i,1],3,5))
> val <- as.numeric(combined.one [i,2])
> container [k,l] <- val
> }
>
> container <- t(container )
>
> Is there any other neat way to do this?
>
> Any help would be appreciated
>
> TM
>
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>



R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Mon Feb 06 02:41:11 2006

This archive was generated by hypermail 2.1.8 : Mon 06 Feb 2006 - 14:40:29 EST