Re: [R] converting character matrix to a dataframe

From: John M. Miyamoto <>
Date: Fri 24 Feb 2006 - 19:58:35 EST

On Fri, 24 Feb 2006, Prof Brian Ripley wrote:

> It is a bit more efficient to use in your apply.
> You could make a copy of (under another name) and remove
> the special-casing of character matrices. This would efficiently give you a
> data frame with character columns, but they would then not be treated 'AsIs'
> in subsequent manipulations. So this is only desirable if efficiency is
> really important (and it seems unlikely to me that it is).
> On Thu, 23 Feb 2006, John M. Miyamoto wrote:
>> Dear R-Help,
>> Suppose I have a character matrix, e.g.,
>> (ch.mat <- matrix(c('a','s','*','f','w','*','k','*','*','f','i','o'),
>> ncol=3))
>> When I convert 'ch.mat' to a dataframe, the columns are converted to
>> factors:
>> The following code is reasonably efficient even if the matrix has
>> arbitrarily many columns.
>> (d3 <- data.frame(apply(ch.mat,2,function(x) data.frame(I(x)))))
>> mode(d3[,1])
>> is.factor(d3[,1])
>> Question: Is there a more efficient method than the last one for
>> converting a character matrix to a dataframe while preventing the
>> automatic conversion of the column vectors to factors?

So I take it that this last solution would be:

(ch.mat <- matrix(c('a','s','*','f','w','*','k','*','*','f','i','o'), ncol=3))

(d4 <- data.frame(apply(ch.mat, 2, function(x) mode(d4[,1])

You're right that I'm not really concerned with computational efficiency, but only minimizing the amount of code that I have to write and remember. The solution seems to be that I should write a function that accomplishes this task, which I have done. Thank you.

John mailing list PLEASE do read the posting guide! Received on Fri Feb 24 20:07:50 2006

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