# Re: [R] combining tables

From: Dimitris Rizopoulos <dimitris.rizopoulos_at_med.kuleuven.be>
Date: Mon 19 Jun 2006 - 17:54:36 EST

one approach is the following:

x <- as.table(c(cats=3,squid=7,pigs=2,dogs=1,slugs=0)) y <- as.table(c(cats=4,dogs=5,slugs=3,crabs=0))

```########################
```

out <- merge(as.data.frame(x), as.data.frame(y), by = "Var1", all = TRUE)
desired.output <- rowSums(out[c("Freq.x", "Freq.y")], na.rm = TRUE) names(desired.output) <- out\$Var1
as.table(desired.output)

I hope it helps.

Best,
Dimitris

Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

```Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm

```
• Original Message ----- From: "Robin Hankin" <r.hankin@noc.soton.ac.uk> To: "RHelp" <r-help@stat.math.ethz.ch> Sent: Monday, June 19, 2006 9:33 AM Subject: [R] combining tables

> Hi
>
> Suppose I have two tables of counts of different animals and I
> wish to pool them so the total of the sum is the sum of the total.
>
> Toy example follows (the real ones are ~10^3 species and ~10^6
> individuals).
> x and y are zoos that have merged and I need a combined inventory
> including animals that are temporarily absent.
>
>
> > (x <- as.table(c(cats=3,squid=7,pigs=2,dogs=1,slugs=0)))
> cats squid pigs dogs slugs
> 3 7 2 1 0
> > (y <- as.table(c(cats=4,dogs=5,slugs=3,crabs=0)))
> cats dogs slugs crabs
> 4 5 3 0
> > (desired.output <- as.table(c
> (cats=7,squid=7,pigs=2,dogs=6,slugs=3,crabs=0)))
> cats squid pigs dogs slugs crabs
> 7 7 2 6 3 0
> >
>
>
>
>
> Note that we have 7 cats altogether, and the crabs correctly show
> as zero counts.
>
>
> How to do this nicely in R?
>
>
>
>
> --
> Robin Hankin
> Uncertainty Analyst
> National Oceanography Centre, Southampton
> European Way, Southampton SO14 3ZH, UK
> tel 023-8059-7743
>
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