Re: [R] getting the smoother matrix from smooth.spline

From: Simon Wood <sw283_at_maths.bath.ac.uk>
Date: Sat 01 Jul 2006 - 02:07:40 EST

smooth.matrix = function(x, df){
  n = length(x);
  A = matrix(0, n, n);
  for(i in 1:n){

        y = rep(0, n); y[i]=1;
        yi = predict(smooth.spline(x, y, df=df),x)$y;
        A[,i]= yi;

}
  (A+t(A))/2;
}

>- Simon Wood, Mathematical Sciences, University of Bath, Bath BA2 7AY
>- +44 (0)1225 386603 www.maths.bath.ac.uk/~sw283/

On Sat, 24 Jun 2006, Gregory Gentlemen wrote:

> Can anyone tell me the trick for obtaining the smoother matrix from smooth.spline when there are non-unique values for x. I have the following code but, of course, it only works when all values of x are unique.
>
> ## get the smoother matrix (x having unique values
> smooth.matrix = function(x, df){
> n = length(x);
> A = matrix(0, n, n);
> for(i in 1:n){
> y = rep(0, n); y[i]=1;
> yi = smooth.spline(x, y, df=df)$y;
> A[,i]= yi;
> }
> (A+t(A))/2;
> }
>
>
> Thanks for any assistance,
> Gregory
>
>
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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Sat Jul 01 02:12:28 2006

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