[R] Permutations with replacement

From: Jesse Albert Canchola <jesse.canchola.b_at_bayer.com>
Date: Sat 19 Aug 2006 - 06:25:30 EST

Is there a simple function or process that will create a matrix of permutations with replacement?

I know that using the combinat package

###### begin R code ######
> library(combinat)
> m <- t(array(unlist(permn(3)), dim = c(3, 6)))

# we can get the permutations, for example 3!=6 # gives us

> m

     [,1] [,2] [,3]

[1,]    1    2    3
[2,]    1    3    2
[3,]    3    1    2
[4,]    3    2    1
[5,]    2    3    1
[6,]    2    1    3

###### end R code ##########

I'd like to include the "with replacement possibilities" such as


and so on. This will eventually be done on 8!=40,320 rather than the development version using 3! as above.

If no function exists (I've Googled on CRAN with no palpable luck), then perhaps this is more of a bootstrap type problem.

Thanks for your help in advance,
Jesse Canchola

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