From: Grant Gillis <grant.j.gillis_at_gmail.com>

Date: Wed, 09 Apr 2008 11:08:28 -0700

data<-cbind(x,y,z)

row.names(data)<-c('a','b','c','d','e','f','g','h')

R-help_at_r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 09 Apr 2008 - 18:11:18 GMT

Date: Wed, 09 Apr 2008 11:08:28 -0700

Hello,

I have what I suspect might be an easy problem but I am new to R and stumped. I have a data set that looks something like this

b<-c(2,3,4,5,6,7,8,9) x<-c(2,3,4,5,6,7,8,9) y<-c(9,8,7,6,5,4,3,2) z<-c(9,8,7,6,1,2,3,4)

data<-cbind(x,y,z)

row.names(data)<-c('a','b','c','d','e','f','g','h')

which gives:

x y z

a 2 9 9

b 3 8 8

c 4 7 7

d 5 6 6

e 6 5 1

f 7 4 2

g 8 3 3

h 9 2 4

I would like to randomize data within columns. The closest I have been able to come permutes data within the columns but keeps rows together along with row names(example below). For some context, eventually I would like use this to generate many data sets and perform calculations on these random data sets (I think I know how to do this but we'll see). So ideally I would like row names to remain the same (in order a through h) and column data to randomize within columns but independently of the other columns. Just shuffle the data deck I guess

> data[permute(1:length(data[,1])),]

x y z

b 3 8 8

c 4 7 7

h 9 2 4

e 6 5 1

f 7 4 2

a 2 9 9

g 8 3 3

d 5 6 6

Thanks in advance for the help and also for the good advice earlier this week.

Cheers

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