Re: [R] g(x,y) = f(x,y) - e(x)- e(y)?

From: Greg Snow <Greg.Snow_at_imail.org>
Date: Wed, 23 Apr 2008 10:52:56 -0600

It is not clear exactly what you want to do by subtracting a vector from a matrix, but look at the "sweep" function, it may do what you want.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.snow_at_imail.org
(801) 408-8111
 
 


> -----Original Message-----
> From: r-help-bounces_at_r-project.org
> [mailto:r-help-bounces_at_r-project.org] On Behalf Of William Simpson
> Sent: Wednesday, April 23, 2008 4:59 AM
> To: Philipp Pagel
> Cc: r-help_at_r-project.org
> Subject: Re: [R] g(x,y) = f(x,y) - e(x)- e(y)?
>
> Thanks Phipp very much for your help. I had meant, given that
> I'd computed the matrix f[x,y] and the vector e[x], how to
> take the difference. What is confusing is how to subtract a
> vector from a matrix. I don't want the recycling rule.
>
> Cheers
> Bill
>
> On Tue, Apr 22, 2008 at 9:53 AM, Philipp Pagel
> <p.pagel_at_wzw.tum.de> wrote:
> >
> > > g(x,y) = f(x,y) - e(x)- e(y)
> > > These are continuous functions. I am not sure how to do
> this with
> > the > discrete equivalents in R.
> >
> > Is this what you are looking for?
> >
> > g <- function(x, y) {
> >
> > f(x,y) - e(x) - e(y)
> > }
> >
> > cu
> > Philipp
> >
> > --
> > Dr. Philipp Pagel
> > Lehrstuhl für Genomorientierte Bioinformatik Technische
> Universität
> > München Wissenschaftszentrum Weihenstephan 85350
> Freising, Germany
> > http://mips.gsf.de/staff/pagel
> >
> > ______________________________________________
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> >
>
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>
______________________________________________ R-help_at_r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Received on Wed 23 Apr 2008 - 16:55:53 GMT

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