Re: [R] Factor to numeric

From: Jorge Ivan Velez <jorgeivanvelez_at_gmail.com>
Date: Thu, 24 Apr 2008 11:53:45 -0400

Hi Jojje,

Try this:

ekob=data.frame(PAP=seq(0,4,by=0.5),CAP=seq(1,5,by=0.5),FAP=seq(4,8,by=0.5)) attach(ekob)

# Option 1
ekob[PAP<1.5 & PAP>0.5 & CAP>1 & CAP<3 & FAP>4,]

# Option 2
subset(ekob,PAP<1.5 & PAP>0.5 & CAP>1 & CAP<3 & FAP>4)

HTH, Jorge

On Thu, Apr 24, 2008 at 11:31 AM, Jojje Andersson <dietaamigo_at_hotmail.com> wrote:

> Hello!
>
> Thanks!
>
> I changed the "," to "." in both datafile and code but the problem remains
> identical.
> Cheers!
> Jojje
>
>
>
>

> > Date: Thu, 24 Apr 2008 09:16:38 +0100> From: ripley_at_stats.ox.ac.uk> To:

> dietaamigo_at_hotmail.com> CC: r-help_at_r-project.org> Subject: Re: [R] Factor
> to numeric> > The decimal point in R is always '.', never ','.> > On Thu, 24
> Apr 2008, Jojje Andersson wrote:> > >> > Hello!> > I have a problem whith a
> data.frame. I want to make a subset where some of the variables have values
> within ceartain limits.> > The variables are proportions like 1,00, 0,54,
> 0,00 etc.> > I don't get it right as R take the variables for factors.> >>
> >> >> ekobsub1 <- subset(ekob, PAP>0,25 & PAP<0,6 & CAP>0,1 & CAP<0,6 &
> FAP>0,1)> > Error in `[.data.frame`(x, r, vars, drop = drop) : object "CAP"
> not found> > In addition: Warning message:> > In Ops.factor(PAP, 0) : > not
> meaningful for factors> >> >>
> ekobn<-as.numeric(as.character(ekob[["PAP"]]))> > Warning message:> > NAs
> introduced by coercion> >> >> > Thanks!> >> > /Jojje> >> >
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